Predict the output or error(s) for the following:

class base

{

public:

void baseFun(){ cout<<"from base"<<endl;}

};

class deri:public base

{

public:

void baseFun(){ cout<< "from derived"<<endl;}

};

void SomeFunc(base *baseObj)

{

baseObj->baseFun();

}

int main()

{

base baseObject;

SomeFunc(&baseObject);

deri deriObject;

SomeFunc(&deriObject);

}

Answer:

from base

from base

Explanation:

As we have seen in the previous case, SomeFunc expects a pointer to a base class. Since a pointer to a derived class object is passed, it treats the argument only as a base class pointer and the corresponding base function is called.