Predict the output or error(s) for the following:

main()

{

char *p="hai friends",*p1;

p1=p;

while(*p!='\0') ++*p++;

printf("%s   %s",p,p1);

}

Answer:

ibj!gsjfoet

Explanation:

                        ++*p++ will be parse in the given order

• *p that is value at the location currently pointed by p will be taken


• ++*p the retrieved value will be incremented


• when ; is encountered the location will be incremented that is p++ will be executed

Hence, in the while loop initial value pointed by p is ‘h’, which is changed to ‘i’ by executing ++*p and pointer moves to point, ‘a’ which is similarly changed to ‘b’ and so on. Similarly blank space is converted to ‘!’. Thus, we obtain value in p becomes “ibj!gsjfoet” and since p reaches ‘\0’ and p1 points to p thus p1 does not print anything.