1. Mound of the Great 2. Mound of the living
3. Mound of the Survivor 4. Mound of the Dead
1. Kadphises I 2. Ugrasena
3. Vikramaditya 4. Pushyamitra
1. Ashoka 2. Kanishka
3. Samudragupta 4. Chandragupta II
1. Ropar 2. Harappa 3. Kalibangan 4. Mohenjodaro
1. Aravalli 2. Vindhya 3. Kalmur 4. Satpura
1. England 2. Finland 3. Canada 4. Korea
1. Hurricanes 2. Tornadoes 3. Typhoons 4. Willy-willies
1. Wind 2. Glaciers 3. Rivers 4. Ground water
int i=1;
while (i<=5)
{
printf("%d",i);
if (i>2)
goto here;
i++;
}
here:
printf("PP");
Compiler error: Undefined label 'here' in function main
1. Dr. Rajendra Prasad
2. Pandit Jawaharlal Nehru
3. C. Rajagopalachari
4. Sardar Vallabhai Patel
The Cripps Proposals include the provision for
a. Full independence for India.
b. Creation of Constitution-making body.
1. a only 2. b only 3. Both a and b 4. Neither a nor b
1. Civil Disobedience Movement
2. Non-Cooperation Movement
3. Quit India Movement
4. Swadeshi Movement
1. Akbar 2. Jahangir 3. Shahjahan 4. Aurangzeb
1. New Delhi 2. Moscow 3. Beijing 4. Guwahati
1. July 1 ,2006 2. January 1, 2007 3. July 1, 2008 4. January 1,2008
1. Thumba 2. Biakonur 3. Sriharikota 4. French Guiana
1. West Bengal 2. Orissa 3. Gujarat 4. Andhra Pradesh
Fraction Exponent
+0.6132789 +04
M*r ^e
1. 1776 2. 1777 3. 1774 4. 1775
1. 1916 2. 1919 3. 1930 4. 1932
1. Andhra - Rayalaseema - Telangana
2. Andhra - Telangana
3. Andhra - Hyderabad
4. Andhra - Rayalaseema
1. 1922 - 1924 2. 1919 - 1920 3. 1921 -1922 4. 1925 - 1926
printf("%p",main);
Some address will be printed.
Function names are just addresses (just like array names are addresses).
clrscr();
No output/error
— e.g. 41=00101001
System.out.println("Equal");
System.out.println("Not Equal");
A. Compiler error
B. Prints "Equal"
C. Prints "Not Equal"
D. None of the above
#define a 50
printf("%d",a);
50
Note :- Use this setting to compile the initial release of a component to other developers.
Note:- When a class is marked with objectpooling attribute it can not be inherited.
ObjectPooling(MinPoolSize := 2, MaxPoolSize := 5, CreationTimeout := 20000)> _
Public Class testingclass
char *p="hai friends",*p1;
p1=p;
while(*p!='\0') ++*p++;
printf("%s %s",p,p1);
ibj!gsjfoet
---- A number of channels in one bus
---- e.g. 32 bit data bus is 32 separate single bit channels
---- Remember that there is no difference between “data” and “instruction” at this level.
---- 8, 16, 32, 64 bit
byte b = 5;
byte c = 4;
byte d = b + c; // does not compile because int cannot fit in a byte
float f = (float)35.67; // implicitly double, so casting to float
float f = 35.67F;
The following example code illustrates some cases of operator
Add reference to EnterpriseServices.
static int i;
static public void main(String[] args)
{
do
{
System.out.println(args[++i]);
} while (i < args.length);
}
---Indicated by an interrupt signal
---Suspend execution of current program
011
0x0001;
Note: assert is a new keyword since J2SE 1.4
For integral types, on a machine that uses two’s complement
Fetch Cycle :Note:- Even though VB6 and V C++ has gone off still many people do ask these old questions again and again. Still there are decent old application which are working with COM very much fine. So interviewer still asks you these questions so that those application’s can be ported to .NET. So let’s play some old music...
int i;
i = 64/square(4);
printf("%d",i);
64
int i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
45545
printf("\nab");
printf("\bsi");
printf("\rha");
hai
interface MyInterface
{
void f();
}
class MyClass implements MyInterface
{
public void f() {}
}
Sorting takes place from the pivot value, which is the first value of the given elements, this is marked bold. The values at the left pointer and right pointer are indicated using L and R respectively.
Since pivot is not yet changed the same process is continued after
cout<<ptr[0];
cout<<ptr[0];
int a[size] = {1,2,3,4,5};
int *b = new int(size);
print(a);
print(b);
int a, *pa, &ra;
pa = &a;
ra = a;
cout <<"a="<<a <<"*pa="<<*pa <<"ra"<<ra ;
Compiler Error: 'ra',reference must be initialized
while (*str = 0) /* programmer meant to write *str != 0 */
{
/* some code here */
str++;
}
What is CCW (COM callable wrapper) ?
How do we ensure that .NET components is compatible with COM ?
struct xx
{
int x;
struct yy
{
char s;
struct xx *p;
};
struct yy *q;
};
Compiler Error
Adding Reference using VS.NET
public:
virtual void baseFun(){ cout<<"from base"<<endl;}
public:
void baseFun(){ cout<< "from derived"<<endl;}
baseObj->baseFun();
base baseObject;
SomeFunc(&baseObject);
deri deriObject;
SomeFunc(&deriObject);
from base
from derived
public:
void baseFun(){ cout<<"from base"<<endl;}
public:
void baseFun(){ cout<< "from derived"<<endl;}
baseObj->baseFun();
base baseObject;
SomeFunc(&baseObject);
deri deriObject;
SomeFunc(&deriObject);
from base
from base
public class TutorialGC
{
public static void main(String [] args)
{
Object a = new Integer(100); // Line1
Object b = new Long(100); // Line2
Object c = new String("100"); // Line3
a = null; // Line4
a = c; // Line5
c = b; // Line6
b = a; // Line7
// Rest of the code here
}
}
struct xx
{
int x=3;
char name[]="hello";
};
struct xx *s;
printf("%d",s->x);
printf("%s",s->name);
Compiler Error
int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} };
int *p,*q;
p=&a[2][2][2];
*q=***a;
printf("%d----%d",*p,*q);
Binom = 1
Binom=(bimom*(f-x+1)/x
Printf binom
Else
Goto 5
Note :- You can get the source code in CD in “CodeDom” folder.
We will try to generate the following code below. The below code
char s[]={'a','b','c','\n','c','\0'};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
77
int i=10;
i=!i>14;
Printf ("i=%d",i);
i=0
int i = 3;
switch (i)
{
default:
System.out.println("default");
case 0:
System.out.println("zero");
case 1:
System.out.println("one");
break;
case 2:
System.out.println("two");
}
assert(a > 0); // throws an AssertionError if a <= 0
assert Expression1 ;
assert Expression1 : Expression2 ;
4.1 printf "Month of sales is : 02/87”
4.2 printf "Price is : 75,000"
5.1 print "Month of sales is : 07/87 "
5.2 print "Price is : 95,000”
6.1 print "Month of sales is : 04/88 "
6.2 print " Price is : 1,10,000"
7.2 print " Price is : 85,000"
Step1: Start
Step2: Read the value of x.
Step3: if (x>0) y-1 else if (x=0) y=0 else x<0) y=-1
Step4: Print y
Step5: Stop.
Step1: Start
Step2: Read the values of x,y and a.
Step3: p=2.5*log(x)+ cos(a*3.14/180)+sqrt(2*x*y)+(x*x-y*y)
Step4: Print p
Step5: Stop.
int i =0;
MessageBox.Show(i.ToString());
MessageBox.Show(Convert.ToString(i));
public:
int bval;
base(){ bval=0;}
public:
int dval;
deri(){ dval=1;}
for(int i=0; i<size; i++,arr++)
cout<<endl;
base BaseArr[5];
SomeFunc(BaseArr,5);
deri DeriArr[5];
SomeFunc(DeriArr,5);
00000
01010
{
ptr = new int(i);
{
delete ptr;
{
cout << "The value is " << *ptr;
cout << "Say i am in someFunc " << endl;
Sample s1= 10;
SomeFunc(s1);
s1.PrintVal();
Say i am in someFunc
Null pointer assignment(Run-time error)
extern:
This is the default for variables declared outside any function. The scope of variables with extern scope is all the code in the entire program.
static:
int b,w;
void Box(int b,int w)
{
this.b = b;
this.w = w;
}
MyBox()
{
super(10,15);
System.out.println(b + "," + w);
}
static public void main(String args[])
{
MyBox box = new MyBox();
}
int c=- -2;
printf("c=%d",c);
It will have only 6 (ie,5+1) null branches. In general,Note :- This question can only be asked when the interviewer does not know what he wants. It was asked to me in one of interview and for 15 minutes he was roaming around the same question in order to get answer from me (requirement was for a simple database project). Beware of such companies and interviewers you can land up no where.
int i=3;
switch(i)
{
default:printf("zero");
case 1: printf("one");
break;
case 2:printf("two");
break;
case 3: printf("three");
break;
}
char *p;
printf("%d %d ",sizeof(*p),sizeof(p));
#define REQUESTED_BLOCKS 512
int x;
char* cp[REQUESTED_BLOCKS];
/* Attempt (in vain, I must add...) to
allocate 512 10KB blocks in memory. */
for (x=0; x< REQUESTED_BLOCKS; x++)
{
cp[x] = (char*) malloc(10000, 1);
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++) {
printf(" %d ",*c);
++q; }
for(j=0;j<5;j++){
printf(" %d ",*p);
++p; }
/* Here, the comma operator is used to separate
three variable declarations. */
int i, j, k;
switch (char_code)
{
case ‘Y’:
case ‘y’: printf(“You answered YES!\n”);
break;
case ‘N’:
case ‘n’: printf(“You answered NO!\n”);
break;
}
a) Guided Media:
switch (char_code)
{
case ‘Y’:
case ‘y’: printf(“You answered YES!\n”);
break;
case ‘N’:
case ‘n’: printf(“You answered NO!\n”);
break;
}
Consider, however, what would happen if an unknown character code were passed to this switch statement. The program would not print anything. It would be a good idea, therefore, to insert a default case where this condition would be taken care of:
...
default: printf(“Unknown response: %d\n”, char_code);
break;
...
void move_cursor(int direction)
{
switch (direction)
{
case UP: cursor_up();
break;
case DOWN: cursor_down();
break;
case LEFT: cursor_left();
break;
case RIGHT: cursor_right();
break;
default: printf(“Logic error on line number ld!!!\n”, __LINE__);
break;
}
}
